Forum d'entraide PHPFrance

esse que ceci est bien ecrit :
if(isset($_POST['pseudo']) and isset($_POST['mess']))

Voila le code en entier
<html>
<head>
<title> testp </title>
<link rel="stylesheet" media="screen" type="text/css" title="blue" href="sombre.css"/>
</head>
<body>
<form action="testmysql.php" method="POST"><p>
Pseudo <input type="text" name="pseudo"/></br>
Message <input type="text" name="mess"/></P>
</form>
<?
if(isset($_POST['pseudo']) and isset($_POST['mess']))
{
$pseudo=$_post['pseudo'];
$mess=$_post['mess'];
mysql_connect("localhost","root");
mysql_select_db("exercice");
mysql_query(Insert into chat value("";"$mess";"$pseudo")
}
else
{
echo "entrer votre pseudo et votre message";
}
mysql_close();
?>
<p>t'chat</p>
<?
mysql_connect("localhost","root");
mysql_select_db("exercice");
$chat=mysql_query(select * from chat order by id);
while($text=mysql_fetch_array($chat))
{
echo $text['pseudo'] ."ecrit". $text['mess'];
}
Mysql_close();
?>

</body>
<html>

Tu y étais presque: fais attention quand tu envoies du SQL à séparer le SQL du PHP : voici un corrigé express:

<html>
<head>
<title> testp </title>
<link rel="stylesheet" media="screen" type="text/css" title="blue" href="sombre.css"/>
</head>
<body>
<form action="testmysql.php" method="POST"><p>
Pseudo <input type="text" name="pseudo"/></br>
Message <input type="text" name="mess"/></P>
</form>
<?
if(isset($_POST['pseudo']) and isset($_POST['mess']))
{
    $pseudo=$_post['pseudo'];
    $mess=$_post['mess'];
    mysql_connect("localhost","root");
    mysql_select_db("exercice");
    mysql_query("Insert into chat value('','". $mess ."','". $pseudo .";");
}
else
{
    echo "entrer votre pseudo et votre message";
}
mysql_close();
?>
<p>t'chat</p>
<?
mysql_connect("localhost","root");
mysql_select_db("exercice");
$chat=mysql_query("select * from chat order by id");
while($text=mysql_fetch_array($chat))
{
    echo $text['pseudo'] ."ecrit". $text['mess'];
}
mysql_close();
?>

</body>
<html>

cela ne marche tjr pas :|
j ai réusie a coriger avan de lire ton message pour le s1er et voissie une nouvel erreur! erreur ligne: 29 : $chat=mysql_query(select * from chat
order by id limit 0,9);
---------------------------------
code:
<html>
<head>
<title> testp </title>
<link rel="stylesheet" media="screen" type="text/css" title="blue" href="sombre.css"/>
</head>
<body>
<form action="testmysql.php" method="POST"><p>
Pseudo <input type="text" name="pseudo"/></br>
Message <input type="text" name="mess"/></P>
</form>
<?
if(isset($_POST['pseudo']) and isset($_POST['mess']))
{
if($_POST['pseudo'] != null and $_POST['mess'] != null)
{
mysql_connect("localhost","root");
mysql_select_db("exercice");
$pseudo=htmlentities($_post['pseudo']);
$mess=htmlentities($_post['mess']);
mysql_query("Insert into chat value('','$mess','$pseudo'");
mysql_close();
}
}
?>
<p>t'chat</p>
<?
mysql_connect("localhost","root");
mysql_select_db("exercice");
$chat=mysql_query(select * from chat order by id limit 0,9);
while($text=mysql_fetch_array($chat))
{
?><p><?echo $text['pseudo'];?> ecrit <?echo $text['mess'];?><?
}
Mysql_close();
?>

</body>
<html>

Tu as toujours la même erreur dans cette ligne: compare ton fichier et ce que j'ai envoyé tout à l'heure pour cette ligne: tu n'as pas isolé le PHP du SQL. Donc tu as une erreur parce que PHP ne reconnait pas le langage SQL

comme ceci
<html>
<head>
<title> testp </title>
<link rel="stylesheet" media="screen" type="text/css" title="blue" href="sombre.css"/>
</head>
<body>
<form action="testmysql.php" method="POST"><p>
Pseudo <input type="text" name="pseudo"/></br>
Message <input type="text" name="mess"/>
<input type="submit"/></P>
</form>
<?
if(isset($_POST['pseudo']) and isset($_POST['mess']))
{
if($_POST['pseudo'] != null and $_POST['mess'] != null)
{
$pseudo=htmlentities($_post['pseudo']);
$mess=htmlentities($_post['mess']);
mysql_connect("localhost","root");
mysql_select_db("exercice");
mysql_query("Insert into chat value('','$mess','$pseudo'");
mysql_close();
}
}
?>
<p>t'chat</p>
<?
mysql_connect("localhost","root");
mysql_select_db("exercice");
$chat=mysql_query("select * from chat order by id limit 0,9");
Mysql_close();
while($text=mysql_fetch_array($chat))
{
?><p><?echo $text['pseudo'];?> ecrit <?echo $text['mess'];?><?
}
?>

</body>
<html>

c'est bon mais il rest un problem !
dans mon t chat tout les mesages avec un ' un . ou des signe bizare n'aparai pas
que fair?
voila le code
<html>
<head>
<title> testp </title>
<link rel="stylesheet" media="screen" type="text/css" title="blue" href="sombre.css"/>
</head>
<body>
<form action="testmysql.php" method="POST"><p>
Pseudo <input type="text" name="pseudo"/></br>
Message <input type="text" name="mess"/>
<input type="submit"/></P>
</form>
<?
if(isset($_POST['pseudo']) and isset($_POST['mess']))
{
if($_POST['pseudo'] != null and $_POST['mess'] != null)
{
$pseudo=htmlentities($_POST['pseudo']);
$mess=htmlentities($_POST['mess']);
mysql_connect("localhost","root");
mysql_select_db("exercice");
mysql_query("Insert into chat value('','". $mess ."','". $pseudo ."')");
mysql_close();
}
}
?>
<p>t'chat</p>
<?
mysql_connect("localhost","root");
mysql_select_db("exercice");
$chat=mysql_query("select * from chat order by id desc limit 0,9");
Mysql_close();
while($text=mysql_fetch_array($chat))
{
?><p><?echo $text['pseudo'];?> ecrit <?echo $text['mess'];?><?
}
?>

</body>
<html>

Réponse ==> ICI

Je pige rien du tout:-|
dsl..
b onne soirée

Forum d'entraide PHPFrance

si variable existe...

si variable existe...